Base | Representation |
---|---|
bin | 1000111010011011111… |
… | …0101011101001100011 |
3 | 112122020120021110021001 |
4 | 2032212332223221203 |
5 | 10002100034224211 |
6 | 154202250412431 |
7 | 14030405421304 |
oct | 2164676535143 |
9 | 478216243231 |
10 | 153125304931 |
11 | 59a38273a95 |
12 | 25815431117 |
13 | 11593bc7411 |
14 | 75a88947ab |
15 | 3eb3175ac1 |
hex | 23a6faba63 |
153125304931 has 2 divisors, whose sum is σ = 153125304932. Its totient is φ = 153125304930.
The previous prime is 153125304877. The next prime is 153125304953. The reversal of 153125304931 is 139403521351.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 153125304931 - 231 = 150977821283 is a prime.
It is a super-2 number, since 2×1531253049312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (153185304931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76562652465 + 76562652466.
It is an arithmetic number, because the mean of its divisors is an integer number (76562652466).
Almost surely, 2153125304931 is an apocalyptic number.
153125304931 is a deficient number, since it is larger than the sum of its proper divisors (1).
153125304931 is an equidigital number, since it uses as much as digits as its factorization.
153125304931 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48600, while the sum is 37.
The spelling of 153125304931 in words is "one hundred fifty-three billion, one hundred twenty-five million, three hundred four thousand, nine hundred thirty-one".
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