1531253123401 has 4 divisors (see below), whose sum is σ = 1531264614400. Its totient is φ = 1531241632404.

The previous prime is 1531253123399. The next prime is 1531253123423. The reversal of 1531253123401 is 1043213521351.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1531253123401 - 2¹ = 1531253123399 is a prime.

It is a super-2 number, since 2×1531253123401² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1531253123441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5543241 + ... + 5812918.

It is an arithmetic number, because the mean of its divisors is an integer number (382816153600).

Almost surely, 2^{1531253123401} is an apocalyptic number.

It is an amenable number.

1531253123401 is a deficient number, since it is larger than the sum of its proper divisors (11490999).

1531253123401 is a wasteful number, since it uses less digits than its factorization.

1531253123401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11490998.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 1531253123401 its reverse (1043213521351), we get a palindrome (2574466644752).

The spelling of 1531253123401 in words is "one trillion, five hundred thirty-one billion, two hundred fifty-three million, one hundred twenty-three thousand, four hundred one".