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153125321131 = 1491027686719
BaseRepresentation
bin1000111010011011111…
…0101111100110101011
3112122020120022021111001
42032212332233212223
510002100040234011
6154202251015431
714030405516446
oct2164676574653
9478216267431
10153125321131
1159a38285182
122581543a577
1311593c018c3
1475a889a65d
153eb317a7c1
hex23a6faf9ab

153125321131 has 4 divisors (see below), whose sum is σ = 154153008000. Its totient is φ = 152097634264.

The previous prime is 153125321117. The next prime is 153125321137. The reversal of 153125321131 is 131123521351.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 153125321131 - 217 = 153125190059 is a prime.

It is a super-2 number, since 2×1531253211312 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 153125321131.

It is not an unprimeable number, because it can be changed into a prime (153125321137) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 513843211 + ... + 513843508.

It is an arithmetic number, because the mean of its divisors is an integer number (38538252000).

Almost surely, 2153125321131 is an apocalyptic number.

153125321131 is a deficient number, since it is larger than the sum of its proper divisors (1027686869).

153125321131 is a wasteful number, since it uses less digits than its factorization.

153125321131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1027686868.

The product of its digits is 2700, while the sum is 28.

Adding to 153125321131 its reverse (131123521351), we get a palindrome (284248842482).

The spelling of 153125321131 in words is "one hundred fifty-three billion, one hundred twenty-five million, three hundred twenty-one thousand, one hundred thirty-one".

Divisors: 1 149 1027686719 153125321131