Base | Representation |
---|---|
bin | 1101111011010101100011… |
… | …1010001010101100011001 |
3 | 2000012220122210020210210211 |
4 | 3132311120322022230121 |
5 | 4001342111303202101 |
6 | 52322415034411121 |
7 | 3140221440556042 |
oct | 336653072125431 |
9 | 60186583223724 |
10 | 15313050053401 |
11 | 49742565aa081 |
12 | 1873931590aa1 |
13 | 8710258c6879 |
14 | 3ad226c918c9 |
15 | 1b84da860c51 |
hex | ded58e8ab19 |
15313050053401 has 8 divisors (see below), whose sum is σ = 15352236887904. Its totient is φ = 15273907777440.
The previous prime is 15313050053387. The next prime is 15313050053437. The reversal of 15313050053401 is 10435005031351.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 15313050053401 - 223 = 15313041664793 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (15313050053501) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10451380 + ... + 11826133.
It is an arithmetic number, because the mean of its divisors is an integer number (1919029610988).
Almost surely, 215313050053401 is an apocalyptic number.
It is an amenable number.
15313050053401 is a deficient number, since it is larger than the sum of its proper divisors (39186834503).
15313050053401 is a wasteful number, since it uses less digits than its factorization.
15313050053401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22279271.
The product of its (nonzero) digits is 13500, while the sum is 31.
Adding to 15313050053401 its reverse (10435005031351), we get a palindrome (25748055084752).
The spelling of 15313050053401 in words is "fifteen trillion, three hundred thirteen billion, fifty million, fifty-three thousand, four hundred one".
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