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15314324131 = 128922035393
BaseRepresentation
bin11100100001100111…
…00000101010100011
31110112021121021100001
432100303200222203
5222330431333011
611011343040431
71051334415211
oct162063405243
943467537301
1015314324131
11654959a427
122b748a0117
1315a09c0972
14a53c85cb1
155e97027c1
hex390ce0aa3

15314324131 has 8 divisors (see below), whose sum is σ = 15336005040. Its totient is φ = 15292660992.

The previous prime is 15314324111. The next prime is 15314324143. The reversal of 15314324131 is 13142341351.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 15314324131 - 25 = 15314324099 is a prime.

It is a super-2 number, since 2×153143241312 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 15314324131.

It is not an unprimeable number, because it can be changed into a prime (15314324111) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2836971 + ... + 2842363.

It is an arithmetic number, because the mean of its divisors is an integer number (1917000630).

Almost surely, 215314324131 is an apocalyptic number.

15314324131 is a deficient number, since it is larger than the sum of its proper divisors (21680909).

15314324131 is a wasteful number, since it uses less digits than its factorization.

15314324131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8885.

The product of its digits is 4320, while the sum is 28.

Adding to 15314324131 its reverse (13142341351), we get a palindrome (28456665482).

The spelling of 15314324131 in words is "fifteen billion, three hundred fourteen million, three hundred twenty-four thousand, one hundred thirty-one".

Divisors: 1 1289 2203 5393 2839667 6951577 11880779 15314324131