Base | Representation |
---|---|
bin | 11100100001101010… |
… | …00000000111101001 |
3 | 1110112022100010122212 |
4 | 32100311000013221 |
5 | 222331031340423 |
6 | 11011355254505 |
7 | 1051340634125 |
oct | 162065000751 |
9 | 43468303585 |
10 | 15314715113 |
11 | 6549837155 |
12 | 2b74a4a435 |
13 | 15a0ac9909 |
14 | a53d48585 |
15 | 5e977d578 |
hex | 390d401e9 |
15314715113 has 2 divisors, whose sum is σ = 15314715114. Its totient is φ = 15314715112.
The previous prime is 15314715089. The next prime is 15314715133. The reversal of 15314715113 is 31151741351.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 15314557504 + 157609 = 123752^2 + 397^2 .
It is a cyclic number.
It is not a de Polignac number, because 15314715113 - 26 = 15314715049 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 15314715113.
It is not a weakly prime, because it can be changed into another prime (15314715133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7657357556 + 7657357557.
It is an arithmetic number, because the mean of its divisors is an integer number (7657357557).
Almost surely, 215314715113 is an apocalyptic number.
It is an amenable number.
15314715113 is a deficient number, since it is larger than the sum of its proper divisors (1).
15314715113 is an equidigital number, since it uses as much as digits as its factorization.
15314715113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6300, while the sum is 32.
The spelling of 15314715113 in words is "fifteen billion, three hundred fourteen million, seven hundred fifteen thousand, one hundred thirteen".
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