1532413054113 has 4 divisors (see below), whose sum is σ = 2043217405488. Its totient is φ = 1021608702740.

The previous prime is 1532413054037. The next prime is 1532413054129. The reversal of 1532413054113 is 3114503142351.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1532413054113 - 2⁹ = 1532413053601 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1532413054153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 255402175683 + ... + 255402175688.

It is an arithmetic number, because the mean of its divisors is an integer number (510804351372).

Almost surely, 2^{1532413054113} is an apocalyptic number.

It is an amenable number.

1532413054113 is a deficient number, since it is larger than the sum of its proper divisors (510804351375).

1532413054113 is an equidigital number, since it uses as much as digits as its factorization.

1532413054113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 510804351374.

The product of its (nonzero) digits is 21600, while the sum is 33.

Adding to 1532413054113 its reverse (3114503142351), we get a palindrome (4646916196464).

The spelling of 1532413054113 in words is "one trillion, five hundred thirty-two billion, four hundred thirteen million, fifty-four thousand, one hundred thirteen".