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153243245137 is a prime number
BaseRepresentation
bin1000111010111000000…
…0100101101001010001
3112122112210012102210211
42032232000211221101
510002320232321022
6154222102324121
714033340043303
oct2165600455121
9478483172724
10153243245137
1159a988a9234
1225848a29641
13115b247c918
1475ba3d5973
153ebd6c0e77
hex23ae025a51

153243245137 has 2 divisors, whose sum is σ = 153243245138. Its totient is φ = 153243245136.

The previous prime is 153243245047. The next prime is 153243245219. The reversal of 153243245137 is 731542342351.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 147658821696 + 5584423441 = 384264^2 + 74729^2 .

It is an emirp because it is prime and its reverse (731542342351) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-153243245137 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 153243245137.

It is not a weakly prime, because it can be changed into another prime (153243245237) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76621622568 + 76621622569.

It is an arithmetic number, because the mean of its divisors is an integer number (76621622569).

Almost surely, 2153243245137 is an apocalyptic number.

It is an amenable number.

153243245137 is a deficient number, since it is larger than the sum of its proper divisors (1).

153243245137 is an equidigital number, since it uses as much as digits as its factorization.

153243245137 is an evil number, because the sum of its binary digits is even.

The product of its digits is 302400, while the sum is 40.

Adding to 153243245137 its reverse (731542342351), we get a palindrome (884785587488).

The spelling of 153243245137 in words is "one hundred fifty-three billion, two hundred forty-three million, two hundred forty-five thousand, one hundred thirty-seven".