Base | Representation |
---|---|
bin | 100010110110110101010000… |
… | …001001010011001101110001 |
3 | 202002210111020221112000002011 |
4 | 202312311100021103031301 |
5 | 130043143200222431114 |
6 | 1302013442150122521 |
7 | 44201450602310362 |
oct | 4266652011231561 |
9 | 662714227460064 |
10 | 153301612311409 |
11 | 44934937648701 |
12 | 1523aa67950441 |
13 | 6770384251123 |
14 | 29bdba2631b69 |
15 | 12acad7b641c4 |
hex | 8b6d50253371 |
153301612311409 has 2 divisors, whose sum is σ = 153301612311410. Its totient is φ = 153301612311408.
The previous prime is 153301612311179. The next prime is 153301612311437. The reversal of 153301612311409 is 904113216103351.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 119984704785009 + 33316907526400 = 10953753^2 + 5772080^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-153301612311409 is a prime.
It is not a weakly prime, because it can be changed into another prime (153301612311709) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76650806155704 + 76650806155705.
It is an arithmetic number, because the mean of its divisors is an integer number (76650806155705).
Almost surely, 2153301612311409 is an apocalyptic number.
It is an amenable number.
153301612311409 is a deficient number, since it is larger than the sum of its proper divisors (1).
153301612311409 is an equidigital number, since it uses as much as digits as its factorization.
153301612311409 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 58320, while the sum is 40.
The spelling of 153301612311409 in words is "one hundred fifty-three trillion, three hundred one billion, six hundred twelve million, three hundred eleven thousand, four hundred nine".
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