Base | Representation |
---|---|
bin | 100010110110110111100110… |
… | …111000101001010010110011 |
3 | 202002210201210012021012002212 |
4 | 202312313212320221102303 |
5 | 130043213340133230021 |
6 | 1302014541131202335 |
7 | 44201600351353514 |
oct | 4266674670512263 |
9 | 662721705235085 |
10 | 153304141305011 |
11 | 44935a15154a64 |
12 | 1523b4528a63ab |
13 | 6770698192448 |
14 | 29bdd6246ca0b |
15 | 12acbd4bba85b |
hex | 8b6de6e294b3 |
153304141305011 has 4 divisors (see below), whose sum is σ = 153307295046024. Its totient is φ = 153300987564000.
The previous prime is 153304141304939. The next prime is 153304141305031. The reversal of 153304141305011 is 110503141403351.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 153304141305011 - 210 = 153304141303987 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (153304141305031) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1576797590 + ... + 1576894811.
It is an arithmetic number, because the mean of its divisors is an integer number (38326823761506).
Almost surely, 2153304141305011 is an apocalyptic number.
153304141305011 is a deficient number, since it is larger than the sum of its proper divisors (3153741013).
153304141305011 is an equidigital number, since it uses as much as digits as its factorization.
153304141305011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3153741012.
The product of its (nonzero) digits is 10800, while the sum is 32.
Adding to 153304141305011 its reverse (110503141403351), we get a palindrome (263807282708362).
The spelling of 153304141305011 in words is "one hundred fifty-three trillion, three hundred four billion, one hundred forty-one million, three hundred five thousand, eleven".
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