Base | Representation |
---|---|
bin | 1000111011001000001… |
… | …1001101001011110001 |
3 | 112122201111202210012121 |
4 | 2032302003031023301 |
5 | 10002440111241431 |
6 | 154232523354241 |
7 | 14035122224542 |
oct | 2166203151361 |
9 | 478644683177 |
10 | 153311040241 |
11 | 5a0230a3747 |
12 | 25867682981 |
13 | 115c3528978 |
14 | 75c54024c9 |
15 | 3ec4613611 |
hex | 23b20cd2f1 |
153311040241 has 8 divisors (see below), whose sum is σ = 155292350720. Its totient is φ = 151330746528.
The previous prime is 153311040221. The next prime is 153311040251. The reversal of 153311040241 is 142040113351.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 153311040241 - 221 = 153308943089 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (153311040221) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 51685 + ... + 556141.
It is an arithmetic number, because the mean of its divisors is an integer number (19411543840).
Almost surely, 2153311040241 is an apocalyptic number.
It is an amenable number.
153311040241 is a deficient number, since it is larger than the sum of its proper divisors (1981310479).
153311040241 is an equidigital number, since it uses as much as digits as its factorization.
153311040241 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 508383.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 153311040241 its reverse (142040113351), we get a palindrome (295351153592).
The spelling of 153311040241 in words is "one hundred fifty-three billion, three hundred eleven million, forty thousand, two hundred forty-one".
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