153312141041 has 2 divisors, whose sum is σ = 153312141042. Its totient is φ = 153312141040.

The previous prime is 153312141019. The next prime is 153312141061. The reversal of 153312141041 is 140141213351.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 152571484816 + 740656225 = 390604^2 + 27215^2 .

It is an emirp because it is prime and its reverse (140141213351) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 153312141041 - 2¹⁰ = 153312140017 is a prime.

It is a super-2 number, since 2×153312141041² (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 153312141041.

It is not a weakly prime, because it can be changed into another prime (153312141061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76656070520 + 76656070521.

It is an arithmetic number, because the mean of its divisors is an integer number (76656070521).

Almost surely, 2^153312141041 is an apocalyptic number.

It is an amenable number.

153312141041 is a deficient number, since it is larger than the sum of its proper divisors (1).

153312141041 is an equidigital number, since it uses as much as digits as its factorization.

153312141041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 153312141041 its reverse (140141213351), we get a palindrome (293453354392).

The spelling of 153312141041 in words is "one hundred fifty-three billion, three hundred twelve million, one hundred forty-one thousand, forty-one".