Base | Representation |
---|---|
bin | 1000111011010000011… |
… | …0110001100110001011 |
3 | 112122210220200001121101 |
4 | 2032310012301212023 |
5 | 10003022423432001 |
6 | 154240154522231 |
7 | 14036021333524 |
oct | 2166406614613 |
9 | 478726601541 |
10 | 153345530251 |
11 | 5a040610591 |
12 | 25877136377 |
13 | 115ca713564 |
14 | 75c9c1d84b |
15 | 3ec7677a01 |
hex | 23b41b198b |
153345530251 has 4 divisors (see below), whose sum is σ = 153346486072. Its totient is φ = 153344574432.
The previous prime is 153345530237. The next prime is 153345530257. The reversal of 153345530251 is 152035543351.
It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.
It is a cyclic number.
It is not a de Polignac number, because 153345530251 - 227 = 153211312523 is a prime.
It is a super-2 number, since 2×1533455302512 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 153345530251.
It is not an unprimeable number, because it can be changed into a prime (153345530257) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 171981 + ... + 579886.
It is an arithmetic number, because the mean of its divisors is an integer number (38336621518).
Almost surely, 2153345530251 is an apocalyptic number.
153345530251 is a deficient number, since it is larger than the sum of its proper divisors (955821).
153345530251 is an equidigital number, since it uses as much as digits as its factorization.
153345530251 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 955820.
The product of its (nonzero) digits is 135000, while the sum is 37.
The spelling of 153345530251 in words is "one hundred fifty-three billion, three hundred forty-five million, five hundred thirty thousand, two hundred fifty-one".
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