Base | Representation |
---|---|
bin | 100010111000010001001100… |
… | …110101010111001111001011 |
3 | 202010010221002111222002112012 |
4 | 202320101030311113033023 |
5 | 130101302344244014123 |
6 | 1302131051020410135 |
7 | 44211544311316124 |
oct | 4270211465271713 |
9 | 663127074862465 |
10 | 153400341001163 |
11 | 449727a03a1583 |
12 | 1525601b9a694b |
13 | 677978955c389 |
14 | 29c488a8bd04b |
15 | 12b0465479378 |
hex | 8b844cd573cb |
153400341001163 has 2 divisors, whose sum is σ = 153400341001164. Its totient is φ = 153400341001162.
The previous prime is 153400341001153. The next prime is 153400341001211. The reversal of 153400341001163 is 361100143004351.
153400341001163 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 153400341001163 - 236 = 153331621524427 is a prime.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (153400341001153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 76700170500581 + 76700170500582.
It is an arithmetic number, because the mean of its divisors is an integer number (76700170500582).
Almost surely, 2153400341001163 is an apocalyptic number.
153400341001163 is a deficient number, since it is larger than the sum of its proper divisors (1).
153400341001163 is an equidigital number, since it uses as much as digits as its factorization.
153400341001163 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12960, while the sum is 32.
The spelling of 153400341001163 in words is "one hundred fifty-three trillion, four hundred billion, three hundred forty-one million, one thousand, one hundred sixty-three".
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