Search a number
-
+
15340141417 is a prime number
BaseRepresentation
bin11100100100101011…
…11111101101101001
31110121002011220222211
432102111333231221
5222404034011132
611014104245121
71052100023236
oct162225775551
943532156884
1015340141417
116562123327
122b814707a1
1315a615cb73
14a5748678d
155ebb02147
hex39257fb69

15340141417 has 2 divisors, whose sum is σ = 15340141418. Its totient is φ = 15340141416.

The previous prime is 15340141409. The next prime is 15340141451. The reversal of 15340141417 is 71414104351.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11055260736 + 4284880681 = 105144^2 + 65459^2 .

It is an emirp because it is prime and its reverse (71414104351) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 15340141417 - 23 = 15340141409 is a prime.

It is not a weakly prime, because it can be changed into another prime (15340141717) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7670070708 + 7670070709.

It is an arithmetic number, because the mean of its divisors is an integer number (7670070709).

Almost surely, 215340141417 is an apocalyptic number.

It is an amenable number.

15340141417 is a deficient number, since it is larger than the sum of its proper divisors (1).

15340141417 is an equidigital number, since it uses as much as digits as its factorization.

15340141417 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6720, while the sum is 31.

Adding to 15340141417 its reverse (71414104351), we get a palindrome (86754245768).

The spelling of 15340141417 in words is "fifteen billion, three hundred forty million, one hundred forty-one thousand, four hundred seventeen".