Search a number
-
+
1534055120113 = 3913339201061
BaseRepresentation
bin10110010100101100110…
…011110111110011110001
312102122122221100111010111
4112110230303313303301
5200113221102320423
63132422445101321
7215555213242015
oct26245463676361
95378587314114
101534055120113
1154165313915a
12209387b57841
13b187895bb59
145436a496545
1529d86ed560d
hex1652ccf7cf1

1534055120113 has 4 divisors (see below), whose sum is σ = 1534094360308. Its totient is φ = 1534015879920.

The previous prime is 1534055120111. The next prime is 1534055120149. The reversal of 1534055120113 is 3110215504351.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1303873948129 + 230181171984 = 1141873^2 + 479772^2 .

It is a cyclic number.

It is not a de Polignac number, because 1534055120113 - 21 = 1534055120111 is a prime.

It is a super-2 number, since 2×15340551201132 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1534055120111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 19561398 + ... + 19639663.

It is an arithmetic number, because the mean of its divisors is an integer number (383523590077).

Almost surely, 21534055120113 is an apocalyptic number.

It is an amenable number.

1534055120113 is a deficient number, since it is larger than the sum of its proper divisors (39240195).

1534055120113 is an equidigital number, since it uses as much as digits as its factorization.

1534055120113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 39240194.

The product of its (nonzero) digits is 9000, while the sum is 31.

The spelling of 1534055120113 in words is "one trillion, five hundred thirty-four billion, fifty-five million, one hundred twenty thousand, one hundred thirteen".

Divisors: 1 39133 39201061 1534055120113