Base | Representation |
---|---|
bin | 11100100101000100… |
… | …01110110100111101 |
3 | 1110121022012220001011 |
4 | 32102202032310331 |
5 | 222410344132203 |
6 | 11014301115221 |
7 | 1052136213034 |
oct | 162242166475 |
9 | 43538186034 |
10 | 15343349053 |
11 | 6563a1426a |
12 | 2b82558b11 |
13 | 15a6a13b86 |
14 | a57a7d71b |
15 | 5ec03776d |
hex | 39288ed3d |
15343349053 has 16 divisors (see below), whose sum is σ = 16637544000. Its totient is φ = 14102363520.
The previous prime is 15343349039. The next prime is 15343349081. The reversal of 15343349053 is 35094334351.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-15343349053 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 15343348997 and 15343349015.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (15343349953) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 58713 + ... + 184753.
It is an arithmetic number, because the mean of its divisors is an integer number (1039846500).
Almost surely, 215343349053 is an apocalyptic number.
It is an amenable number.
15343349053 is a deficient number, since it is larger than the sum of its proper divisors (1294194947).
15343349053 is a wasteful number, since it uses less digits than its factorization.
15343349053 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 126252.
The product of its (nonzero) digits is 291600, while the sum is 40.
The spelling of 15343349053 in words is "fifteen billion, three hundred forty-three million, three hundred forty-nine thousand, fifty-three".
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