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1534632113 = 7219233159
BaseRepresentation
bin101101101111000…
…1010000010110001
310221221200101111102
41123132022002301
511120331211423
6412140254145
753013105050
oct13336120261
93857611442
101534632113
11718294903
12369b41355
131b5c29751
14107b5a397
158eadac28
hex5b78a0b1

1534632113 has 4 divisors (see below), whose sum is σ = 1753865280. Its totient is φ = 1315398948.

The previous prime is 1534632103. The next prime is 1534632149. The reversal of 1534632113 is 3112364351.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1534632113 - 222 = 1530437809 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1534632103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 109616573 + ... + 109616586.

It is an arithmetic number, because the mean of its divisors is an integer number (438466320).

Almost surely, 21534632113 is an apocalyptic number.

It is an amenable number.

1534632113 is a deficient number, since it is larger than the sum of its proper divisors (219233167).

1534632113 is an equidigital number, since it uses as much as digits as its factorization.

1534632113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 219233166.

The product of its digits is 6480, while the sum is 29.

The square root of 1534632113 is about 39174.3808247176. The cubic root of 1534632113 is about 1153.4570485437.

Adding to 1534632113 its reverse (3112364351), we get a palindrome (4646996464).

The spelling of 1534632113 in words is "one billion, five hundred thirty-four million, six hundred thirty-two thousand, one hundred thirteen".

Divisors: 1 7 219233159 1534632113