Base | Representation |
---|---|
bin | 10110010101100110100… |
… | …001011001000011110001 |
3 | 12102202011102020212110102 |
4 | 112111212201121003301 |
5 | 200122211434312342 |
6 | 3133102513442145 |
7 | 215621211140432 |
oct | 26254641310361 |
9 | 5382142225412 |
10 | 1535023354097 |
11 | 541aaa735732 |
12 | 2095b8270355 |
13 | b19a142627c |
14 | 5441ccd5489 |
15 | 29de1ede832 |
hex | 165668590f1 |
1535023354097 has 2 divisors, whose sum is σ = 1535023354098. Its totient is φ = 1535023354096.
The previous prime is 1535023354013. The next prime is 1535023354211. The reversal of 1535023354097 is 7904533205351.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1266342851761 + 268680502336 = 1125319^2 + 518344^2 .
It is a cyclic number.
It is not a de Polignac number, because 1535023354097 - 226 = 1534956245233 is a prime.
It is not a weakly prime, because it can be changed into another prime (1535023324097) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 767511677048 + 767511677049.
It is an arithmetic number, because the mean of its divisors is an integer number (767511677049).
Almost surely, 21535023354097 is an apocalyptic number.
It is an amenable number.
1535023354097 is a deficient number, since it is larger than the sum of its proper divisors (1).
1535023354097 is an equidigital number, since it uses as much as digits as its factorization.
1535023354097 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1701000, while the sum is 47.
The spelling of 1535023354097 in words is "one trillion, five hundred thirty-five billion, twenty-three million, three hundred fifty-four thousand, ninety-seven".
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