Base | Representation |
---|---|
bin | 11100100110100100… |
… | …11111011100101001 |
3 | 1110122012000121221021 |
4 | 32103102133130221 |
5 | 222422114000131 |
6 | 11015432212441 |
7 | 1052351563264 |
oct | 162322373451 |
9 | 43565017837 |
10 | 15356000041 |
11 | 6570075128 |
12 | 2b8683a121 |
13 | 15a9523275 |
14 | a59613cdb |
15 | 5ed1d5e11 |
hex | 39349f729 |
15356000041 has 4 divisors (see below), whose sum is σ = 15358720212. Its totient is φ = 15353279872.
The previous prime is 15356000027. The next prime is 15356000053. The reversal of 15356000041 is 14000065351.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 4947715600 + 10408284441 = 70340^2 + 102021^2 .
It is a cyclic number.
It is not a de Polignac number, because 15356000041 - 27 = 15355999913 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (15356000021) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1351600 + ... + 1362913.
It is an arithmetic number, because the mean of its divisors is an integer number (3839680053).
Almost surely, 215356000041 is an apocalyptic number.
It is an amenable number.
15356000041 is a deficient number, since it is larger than the sum of its proper divisors (2720171).
15356000041 is an equidigital number, since it uses as much as digits as its factorization.
15356000041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2720170.
The product of its (nonzero) digits is 1800, while the sum is 25.
Adding to 15356000041 its reverse (14000065351), we get a palindrome (29356065392).
The spelling of 15356000041 in words is "fifteen billion, three hundred fifty-six million, forty-one", and thus it is an aban number.
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