Base | Representation |
---|---|
bin | 100011000001000000101111… |
… | …111011001100110001001001 |
3 | 202012021100220000202100111112 |
4 | 203001000233323030301021 |
5 | 130141123324230211241 |
6 | 1303311052520540105 |
7 | 44303134044464612 |
oct | 4301005773146111 |
9 | 665240800670445 |
10 | 154001151413321 |
11 | 45084581197793 |
12 | 15332556021635 |
13 | 67c1328076ab4 |
14 | 2a059a463cc09 |
15 | 12c0dcb5291eb |
hex | 8c102feccc49 |
154001151413321 has 2 divisors, whose sum is σ = 154001151413322. Its totient is φ = 154001151413320.
The previous prime is 154001151413201. The next prime is 154001151413341. The reversal of 154001151413321 is 123314151100451.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 100674353062921 + 53326798350400 = 10033661^2 + 7302520^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-154001151413321 is a prime.
It is not a weakly prime, because it can be changed into another prime (154001151413341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77000575706660 + 77000575706661.
It is an arithmetic number, because the mean of its divisors is an integer number (77000575706661).
Almost surely, 2154001151413321 is an apocalyptic number.
It is an amenable number.
154001151413321 is a deficient number, since it is larger than the sum of its proper divisors (1).
154001151413321 is an equidigital number, since it uses as much as digits as its factorization.
154001151413321 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7200, while the sum is 32.
The spelling of 154001151413321 in words is "one hundred fifty-four trillion, one billion, one hundred fifty-one million, four hundred thirteen thousand, three hundred twenty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •