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1540414000241 is a prime number
BaseRepresentation
bin10110011010100111110…
…101000100110001110001
312110021002002201001210022
4112122213311010301301
5200214231441001431
63135353442013225
7216201615651104
oct26324765046161
95407062631708
101540414000241
115443165a9996
1220a661647215
13b235019ca0c
14547b0c0473b
152a10a3ad07b
hex166a7d44c71

1540414000241 has 2 divisors, whose sum is σ = 1540414000242. Its totient is φ = 1540414000240.

The previous prime is 1540414000211. The next prime is 1540414000249. The reversal of 1540414000241 is 1420004140451.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1527995126641 + 12418873600 = 1236121^2 + 111440^2 .

It is a cyclic number.

It is not a de Polignac number, because 1540414000241 - 210 = 1540413999217 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1540414000241.

It is not a weakly prime, because it can be changed into another prime (1540414000249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 770207000120 + 770207000121.

It is an arithmetic number, because the mean of its divisors is an integer number (770207000121).

Almost surely, 21540414000241 is an apocalyptic number.

It is an amenable number.

1540414000241 is a deficient number, since it is larger than the sum of its proper divisors (1).

1540414000241 is an equidigital number, since it uses as much as digits as its factorization.

1540414000241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2560, while the sum is 26.

Adding to 1540414000241 its reverse (1420004140451), we get a palindrome (2960418140692).

The spelling of 1540414000241 in words is "one trillion, five hundred forty billion, four hundred fourteen million, two hundred forty-one", and thus it is an aban number.