Base | Representation |
---|---|
bin | 10110011010101000011… |
… | …100110101101111111010 |
3 | 12110021002211022200002211 |
4 | 112122220130311233322 |
5 | 200214242123040232 |
6 | 3135354453245334 |
7 | 216202103365261 |
oct | 26325034655772 |
9 | 5407084280084 |
10 | 1540424424442 |
11 | 544321479832 |
12 | 20a66503384a |
13 | b23523ac697 |
14 | 547b23595d8 |
15 | 2a10b26ba47 |
hex | 166a8735bfa |
1540424424442 has 4 divisors (see below), whose sum is σ = 2310636636666. Its totient is φ = 770212212220.
The previous prime is 1540424424439. The next prime is 1540424424521. The reversal of 1540424424442 is 2444244240451.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1132843051201 + 407581373241 = 1064351^2 + 638421^2 .
It is a super-2 number, since 2×15404244244422 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1540424424395 and 1540424424404.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 385106106109 + ... + 385106106112.
Almost surely, 21540424424442 is an apocalyptic number.
1540424424442 is a deficient number, since it is larger than the sum of its proper divisors (770212212224).
1540424424442 is an equidigital number, since it uses as much as digits as its factorization.
1540424424442 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 770212212223.
The product of its (nonzero) digits is 655360, while the sum is 40.
Adding to 1540424424442 its reverse (2444244240451), we get a palindrome (3984668664893).
The spelling of 1540424424442 in words is "one trillion, five hundred forty billion, four hundred twenty-four million, four hundred twenty-four thousand, four hundred forty-two".
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