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154044123044113 is a prime number
BaseRepresentation
bin100011000001101000110001…
…001110111101100100010001
3202012102110210210110101002201
4203001220301032331210101
5130142324330444402423
61303342520532043201
744306214654354211
oct4301506116754421
9665373723411081
10154044123044113
11450a0822599a45
121533a949163501
1367c53b5989c73
142a07abd74a241
1512c2093d4e2ad
hex8c1a313bd911

154044123044113 has 2 divisors, whose sum is σ = 154044123044114. Its totient is φ = 154044123044112.

The previous prime is 154044123044093. The next prime is 154044123044137. The reversal of 154044123044113 is 311440321440451.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 131091668523729 + 22952454520384 = 11449527^2 + 4790872^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-154044123044113 is a prime.

It is a super-3 number, since 3×1540441230441133 (a number of 44 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (154044123074113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77022061522056 + 77022061522057.

It is an arithmetic number, because the mean of its divisors is an integer number (77022061522057).

Almost surely, 2154044123044113 is an apocalyptic number.

It is an amenable number.

154044123044113 is a deficient number, since it is larger than the sum of its proper divisors (1).

154044123044113 is an equidigital number, since it uses as much as digits as its factorization.

154044123044113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 92160, while the sum is 37.

Adding to 154044123044113 its reverse (311440321440451), we get a palindrome (465484444484564).

The spelling of 154044123044113 in words is "one hundred fifty-four trillion, forty-four billion, one hundred twenty-three million, forty-four thousand, one hundred thirteen".