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154083227713 is a prime number
BaseRepresentation
bin1000111110000000010…
…0110111100001000001
3112201201022202222021121
42033200010313201001
510011030301241323
6154441310152241
714063216553142
oct2174004674101
9481638688247
10154083227713
115a389a68608
1225a421b2681
13116b74c142c
147659babac9
15401c2e4a5d
hex23e0137841

154083227713 has 2 divisors, whose sum is σ = 154083227714. Its totient is φ = 154083227712.

The previous prime is 154083227699. The next prime is 154083227747. The reversal of 154083227713 is 317722380451.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 122869878784 + 31213348929 = 350528^2 + 176673^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-154083227713 is a prime.

It is a super-2 number, since 2×1540832277132 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 154083227713.

It is not a weakly prime, because it can be changed into another prime (154083227783) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77041613856 + 77041613857.

It is an arithmetic number, because the mean of its divisors is an integer number (77041613857).

Almost surely, 2154083227713 is an apocalyptic number.

It is an amenable number.

154083227713 is a deficient number, since it is larger than the sum of its proper divisors (1).

154083227713 is an equidigital number, since it uses as much as digits as its factorization.

154083227713 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 282240, while the sum is 43.

The spelling of 154083227713 in words is "one hundred fifty-four billion, eighty-three million, two hundred twenty-seven thousand, seven hundred thirteen".