Base | Representation |
---|---|
bin | 10110011011001011100… |
… | …010100101001111000011 |
3 | 12110022121212002010100212 |
4 | 112123023202211033003 |
5 | 200221443330212402 |
6 | 3135533123304335 |
7 | 216222512333432 |
oct | 26331342451703 |
9 | 5408555063325 |
10 | 1541013132227 |
11 | 5445a3814698 |
12 | 20a7aa21b0ab |
13 | b241735349a |
14 | 5482a603119 |
15 | 2a142ca8952 |
hex | 166cb8a53c3 |
1541013132227 has 2 divisors, whose sum is σ = 1541013132228. Its totient is φ = 1541013132226.
The previous prime is 1541013132121. The next prime is 1541013132257. The reversal of 1541013132227 is 7222313101451.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1541013132227 - 224 = 1540996355011 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1541013132193 and 1541013132202.
It is not a weakly prime, because it can be changed into another prime (1541013132257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 770506566113 + 770506566114.
It is an arithmetic number, because the mean of its divisors is an integer number (770506566114).
Almost surely, 21541013132227 is an apocalyptic number.
1541013132227 is a deficient number, since it is larger than the sum of its proper divisors (1).
1541013132227 is an equidigital number, since it uses as much as digits as its factorization.
1541013132227 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10080, while the sum is 32.
Adding to 1541013132227 its reverse (7222313101451), we get a palindrome (8763326233678).
The spelling of 1541013132227 in words is "one trillion, five hundred forty-one billion, thirteen million, one hundred thirty-two thousand, two hundred twenty-seven".
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