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154104652355041 is a prime number
BaseRepresentation
bin100011000010100001001001…
…000011111101010111100001
3202012122021001012000221221101
4203002201021003331113201
5130144322312000330131
61303430411105154401
744313456642124363
oct4302411103752741
9665567035027841
10154104652355041
1145114463833153
121534a62032ba01
1367cb010c9268b
142a0a9c2624d33
1512c3937ca9c61
hex8c28490fd5e1

154104652355041 has 2 divisors, whose sum is σ = 154104652355042. Its totient is φ = 154104652355040.

The previous prime is 154104652355011. The next prime is 154104652355047. The reversal of 154104652355041 is 140553256401451.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 114154351964416 + 39950300390625 = 10684304^2 + 6320625^2 .

It is a cyclic number.

It is not a de Polignac number, because 154104652355041 - 25 = 154104652355009 is a prime.

It is a super-2 number, since 2×1541046523550412 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 154104652354982 and 154104652355000.

It is not a weakly prime, because it can be changed into another prime (154104652355047) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77052326177520 + 77052326177521.

It is an arithmetic number, because the mean of its divisors is an integer number (77052326177521).

Almost surely, 2154104652355041 is an apocalyptic number.

It is an amenable number.

154104652355041 is a deficient number, since it is larger than the sum of its proper divisors (1).

154104652355041 is an equidigital number, since it uses as much as digits as its factorization.

154104652355041 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1440000, while the sum is 46.

The spelling of 154104652355041 in words is "one hundred fifty-four trillion, one hundred four billion, six hundred fifty-two million, three hundred fifty-five thousand, forty-one".