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154113312125321 is a prime number
BaseRepresentation
bin100011000010101001001101…
…001110010111000110001001
3202012200002101200220212111222
4203002221031032113012021
5130144443030401002241
61303434402254131425
744314214354013143
oct4302511516270611
9665602350825458
10154113312125321
11451180a7a7279a
12153502384b0b75
1367cba910ca8c3
142a0b1a4793c93
1512c3c9317ca4b
hex8c2a4d397189

154113312125321 has 2 divisors, whose sum is σ = 154113312125322. Its totient is φ = 154113312125320.

The previous prime is 154113312125303. The next prime is 154113312125341. The reversal of 154113312125321 is 123521213311451.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 92067191377225 + 62046120748096 = 9595165^2 + 7876936^2 .

It is a cyclic number.

It is not a de Polignac number, because 154113312125321 - 222 = 154113307931017 is a prime.

It is a super-2 number, since 2×1541133121253212 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (154113312125341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77056656062660 + 77056656062661.

It is an arithmetic number, because the mean of its divisors is an integer number (77056656062661).

Almost surely, 2154113312125321 is an apocalyptic number.

It is an amenable number.

154113312125321 is a deficient number, since it is larger than the sum of its proper divisors (1).

154113312125321 is an equidigital number, since it uses as much as digits as its factorization.

154113312125321 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 21600, while the sum is 35.

Adding to 154113312125321 its reverse (123521213311451), we get a palindrome (277634525436772).

The spelling of 154113312125321 in words is "one hundred fifty-four trillion, one hundred thirteen billion, three hundred twelve million, one hundred twenty-five thousand, three hundred twenty-one".