Base | Representation |
---|---|
bin | 1110000001000110001110… |
… | …1001010100011110011001 |
3 | 2000120101002210012020120212 |
4 | 3200101203221110132121 |
5 | 4010002301143343301 |
6 | 52440103124500505 |
7 | 3150324041122430 |
oct | 340214351243631 |
9 | 60511083166525 |
10 | 15412014434201 |
11 | 4a022203a3140 |
12 | 188ab5054a735 |
13 | 87a4679a7588 |
14 | 3b3d34572117 |
15 | 1bad7dbd04bb |
hex | e0463a54799 |
15412014434201 has 16 divisors (see below), whose sum is σ = 19326048294528. Its totient is φ = 11939943609600.
The previous prime is 15412014434149. The next prime is 15412014434203. The reversal of 15412014434201 is 10243441021451.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-15412014434201 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (15412014434203) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 578472320 + ... + 578498961.
It is an arithmetic number, because the mean of its divisors is an integer number (1207878018408).
Almost surely, 215412014434201 is an apocalyptic number.
15412014434201 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
15412014434201 is a deficient number, since it is larger than the sum of its proper divisors (3914033860327).
15412014434201 is a wasteful number, since it uses less digits than its factorization.
15412014434201 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1156971472.
The product of its (nonzero) digits is 15360, while the sum is 32.
Adding to 15412014434201 its reverse (10243441021451), we get a palindrome (25655455455652).
The spelling of 15412014434201 in words is "fifteen trillion, four hundred twelve billion, fourteen million, four hundred thirty-four thousand, two hundred one".
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