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154154713241 is a prime number
BaseRepresentation
bin1000111110010001010…
…1100100000010011001
3112201220022021210222202
42033210111210002121
510011202101310431
6154452342255545
714065045304564
oct2174425440231
9481808253882
10154154713241
115a416353761
1225a621275b5
13116c9260169
1476654994db
1540237158cb
hex23e4564099

154154713241 has 2 divisors, whose sum is σ = 154154713242. Its totient is φ = 154154713240.

The previous prime is 154154713187. The next prime is 154154713247. The reversal of 154154713241 is 142317451451.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 131475859216 + 22678854025 = 362596^2 + 150595^2 .

It is a cyclic number.

It is not a de Polignac number, because 154154713241 - 234 = 136974844057 is a prime.

It is a super-2 number, since 2×1541547132412 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 154154713195 and 154154713204.

It is not a weakly prime, because it can be changed into another prime (154154713247) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77077356620 + 77077356621.

It is an arithmetic number, because the mean of its divisors is an integer number (77077356621).

Almost surely, 2154154713241 is an apocalyptic number.

It is an amenable number.

154154713241 is a deficient number, since it is larger than the sum of its proper divisors (1).

154154713241 is an equidigital number, since it uses as much as digits as its factorization.

154154713241 is an evil number, because the sum of its binary digits is even.

The product of its digits is 67200, while the sum is 38.

The spelling of 154154713241 in words is "one hundred fifty-four billion, one hundred fifty-four million, seven hundred thirteen thousand, two hundred forty-one".