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15423425032019 is a prime number
BaseRepresentation
bin1110000001110000101111…
…0001010010111101010011
32000121110120000020200010212
43200130023301102331103
54010144133302011034
652445231301314335
73151206564446444
oct340341361227523
960543500220125
1015423425032019
114a07046385174
1218911b5a059ab
1387b5659b41c4
143b46d7ba52cb
151bb2ea8282ce
hexe070bc52f53

15423425032019 has 2 divisors, whose sum is σ = 15423425032020. Its totient is φ = 15423425032018.

The previous prime is 15423425032013. The next prime is 15423425032079. The reversal of 15423425032019 is 91023052432451.

15423425032019 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 15423425032019 - 24 = 15423425032003 is a prime.

It is a super-2 number, since 2×154234250320192 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (15423425032013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7711712516009 + 7711712516010.

It is an arithmetic number, because the mean of its divisors is an integer number (7711712516010).

Almost surely, 215423425032019 is an apocalyptic number.

15423425032019 is a deficient number, since it is larger than the sum of its proper divisors (1).

15423425032019 is an equidigital number, since it uses as much as digits as its factorization.

15423425032019 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 259200, while the sum is 41.

The spelling of 15423425032019 in words is "fifteen trillion, four hundred twenty-three billion, four hundred twenty-five million, thirty-two thousand, nineteen".