Base | Representation |
---|---|
bin | 1110000001110001000100… |
… | …0101111111001010011011 |
3 | 2000121110210020022002110112 |
4 | 3200130101011333022123 |
5 | 4010144324132421133 |
6 | 52445244211434535 |
7 | 3151212030536513 |
oct | 340342105771233 |
9 | 60543706262415 |
10 | 15423514342043 |
11 | 4a07091835105 |
12 | 189121b8b5a4b |
13 | 87b57b354082 |
14 | 3b47059b2843 |
15 | 1bb3035ba648 |
hex | e071117f29b |
15423514342043 has 2 divisors, whose sum is σ = 15423514342044. Its totient is φ = 15423514342042.
The previous prime is 15423514342037. The next prime is 15423514342087. The reversal of 15423514342043 is 34024341532451.
15423514342043 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 15423514342043 - 222 = 15423510147739 is a prime.
It is a super-2 number, since 2×154235143420432 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (15423510342043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7711757171021 + 7711757171022.
It is an arithmetic number, because the mean of its divisors is an integer number (7711757171022).
Almost surely, 215423514342043 is an apocalyptic number.
15423514342043 is a deficient number, since it is larger than the sum of its proper divisors (1).
15423514342043 is an equidigital number, since it uses as much as digits as its factorization.
15423514342043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 691200, while the sum is 41.
Adding to 15423514342043 its reverse (34024341532451), we get a palindrome (49447855874494).
The spelling of 15423514342043 in words is "fifteen trillion, four hundred twenty-three billion, five hundred fourteen million, three hundred forty-two thousand, forty-three".
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