Base | Representation |
---|---|
bin | 10110011100100000100… |
… | …011100010100011001011 |
3 | 12110110022020221102000222 |
4 | 112130200203202203023 |
5 | 200232403444243411 |
6 | 3140330434220255 |
7 | 216303041654651 |
oct | 26344043424313 |
9 | 5413266842028 |
10 | 1542439446731 |
11 | 545165946907 |
12 | 20ab27a2468b |
13 | b25b39b6571 |
14 | 54923c04dd1 |
15 | 2a1c80ea4db |
hex | 167208e28cb |
1542439446731 has 2 divisors, whose sum is σ = 1542439446732. Its totient is φ = 1542439446730.
The previous prime is 1542439446659. The next prime is 1542439446781. The reversal of 1542439446731 is 1376449342451.
It is a strong prime.
It is an emirp because it is prime and its reverse (1376449342451) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1542439446731 - 214 = 1542439430347 is a prime.
It is a super-2 number, since 2×15424394467312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1542439446781) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 771219723365 + 771219723366.
It is an arithmetic number, because the mean of its divisors is an integer number (771219723366).
Almost surely, 21542439446731 is an apocalyptic number.
1542439446731 is a deficient number, since it is larger than the sum of its proper divisors (1).
1542439446731 is an equidigital number, since it uses as much as digits as its factorization.
1542439446731 is an evil number, because the sum of its binary digits is even.
The product of its digits is 8709120, while the sum is 53.
The spelling of 1542439446731 in words is "one trillion, five hundred forty-two billion, four hundred thirty-nine million, four hundred forty-six thousand, seven hundred thirty-one".
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