1543053214041 has 4 divisors (see below), whose sum is σ = 2057404285392. Its totient is φ = 1028702142692.

The previous prime is 1543053214037. The next prime is 1543053214063. The reversal of 1543053214041 is 1404123503451.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1543053214041 - 2² = 1543053214037 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1543053213993 and 1543053214011.

It is not an unprimeable number, because it can be changed into a prime (1543053214141) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 257175535671 + ... + 257175535676.

It is an arithmetic number, because the mean of its divisors is an integer number (514351071348).

Almost surely, 2^{1543053214041} is an apocalyptic number.

It is an amenable number.

1543053214041 is a deficient number, since it is larger than the sum of its proper divisors (514351071351).

1543053214041 is an equidigital number, since it uses as much as digits as its factorization.

1543053214041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 514351071350.

The product of its (nonzero) digits is 28800, while the sum is 33.

Adding to 1543053214041 its reverse (1404123503451), we get a palindrome (2947176717492).

The spelling of 1543053214041 in words is "one trillion, five hundred forty-three billion, fifty-three million, two hundred fourteen thousand, forty-one".