15434113129 has 2 divisors, whose sum is σ = 15434113130. Its totient is φ = 15434113128.

The previous prime is 15434113069. The next prime is 15434113139. The reversal of 15434113129 is 92131143451.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13519875625 + 1914237504 = 116275^2 + 43752^2 .

It is an emirp because it is prime and its reverse (92131143451) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 15434113129 - 2²³ = 15425724521 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 15434113094 and 15434113103.

It is not a weakly prime, because it can be changed into another prime (15434113139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7717056564 + 7717056565.

It is an arithmetic number, because the mean of its divisors is an integer number (7717056565).

Almost surely, 2^15434113129 is an apocalyptic number.

It is an amenable number.

15434113129 is a deficient number, since it is larger than the sum of its proper divisors (1).

15434113129 is an equidigital number, since it uses as much as digits as its factorization.

15434113129 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 12960, while the sum is 34.

The spelling of 15434113129 in words is "fifteen billion, four hundred thirty-four million, one hundred thirteen thousand, one hundred twenty-nine".