Base | Representation |
---|---|
bin | 100011001000100011111110… |
… | …100011010100100111011010 |
3 | 202021002222011110110111120122 |
4 | 203020203332203110213122 |
5 | 130223123442103110432 |
6 | 1304345303045153242 |
7 | 44355462665613431 |
oct | 4310437643244732 |
9 | 667088143414518 |
10 | 154520014113242 |
11 | 4526462a702888 |
12 | 153b70200bb822 |
13 | 682b23708bb6b |
14 | 2a22b46a9a118 |
15 | 12ce648125612 |
hex | 8c88fe8d49da |
154520014113242 has 4 divisors (see below), whose sum is σ = 231780021169866. Its totient is φ = 77260007056620.
The previous prime is 154520014113217. The next prime is 154520014113251. The reversal of 154520014113242 is 242311410025451.
154520014113242 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 138821627143081 + 15698386970161 = 11782259^2 + 3962119^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 38630003528309 + ... + 38630003528312.
Almost surely, 2154520014113242 is an apocalyptic number.
154520014113242 is a deficient number, since it is larger than the sum of its proper divisors (77260007056624).
154520014113242 is an equidigital number, since it uses as much as digits as its factorization.
154520014113242 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 77260007056623.
The product of its (nonzero) digits is 38400, while the sum is 35.
Adding to 154520014113242 its reverse (242311410025451), we get a palindrome (396831424138693).
The spelling of 154520014113242 in words is "one hundred fifty-four trillion, five hundred twenty billion, fourteen million, one hundred thirteen thousand, two hundred forty-two".
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