15497113 has 2 divisors, whose sum is σ = 15497114. Its totient is φ = 15497112.

The previous prime is 15497093. The next prime is 15497123. The reversal of 15497113 is 31179451.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8928144 + 6568969 = 2988^2 + 2563^2 .

It is an emirp because it is prime and its reverse (31179451) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-15497113 is a prime.

It is a super-2 number, since 2×15497113² = 480321022669538, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (15497123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7748556 + 7748557.

It is an arithmetic number, because the mean of its divisors is an integer number (7748557).

Almost surely, 2^15497113 is an apocalyptic number.

It is an amenable number.

15497113 is a deficient number, since it is larger than the sum of its proper divisors (1).

15497113 is an equidigital number, since it uses as much as digits as its factorization.

15497113 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 3780, while the sum is 31.

The square root of 15497113 is about 3936.6372705648. The cubic root of 15497113 is about 249.3160666469.

The spelling of 15497113 in words is "fifteen million, four hundred ninety-seven thousand, one hundred thirteen".