Base | Representation |
---|---|
bin | 10110100011101001011… |
… | …110001110110111111011 |
3 | 12111012002111111012210011 |
4 | 112203221132032313323 |
5 | 200344103420240011 |
6 | 3144035235002351 |
7 | 216664024111414 |
oct | 26435136166773 |
9 | 5435074435704 |
10 | 1550105243131 |
11 | 548439aa9135 |
12 | 2105071393b7 |
13 | b3235c14473 |
14 | 5504dd5480b |
15 | 2a4c60cc621 |
hex | 168e978edfb |
1550105243131 has 2 divisors, whose sum is σ = 1550105243132. Its totient is φ = 1550105243130.
The previous prime is 1550105243077. The next prime is 1550105243153. The reversal of 1550105243131 is 1313425010551.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1550105243131 - 213 = 1550105234939 is a prime.
It is a super-2 number, since 2×15501052431312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1550105243093 and 1550105243102.
It is not a weakly prime, because it can be changed into another prime (1550105243191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 775052621565 + 775052621566.
It is an arithmetic number, because the mean of its divisors is an integer number (775052621566).
Almost surely, 21550105243131 is an apocalyptic number.
1550105243131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1550105243131 is an equidigital number, since it uses as much as digits as its factorization.
1550105243131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9000, while the sum is 31.
The spelling of 1550105243131 in words is "one trillion, five hundred fifty billion, one hundred five million, two hundred forty-three thousand, one hundred thirty-one".
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