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155072056793 is a prime number
BaseRepresentation
bin1001000001101100000…
…0111100110111011001
3112211021020102200202212
42100123000330313121
510020041421304133
6155123352204505
714126554506563
oct2203300746731
9484236380685
10155072056793
115a847151525
1226079399735
1311814319ab4
14771124c333
15407901b148
hex241b03cdd9

155072056793 has 2 divisors, whose sum is σ = 155072056794. Its totient is φ = 155072056792.

The previous prime is 155072056771. The next prime is 155072056859. The reversal of 155072056793 is 397650270551.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 112930946704 + 42141110089 = 336052^2 + 205283^2 .

It is an emirp because it is prime and its reverse (397650270551) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 155072056793 - 210 = 155072055769 is a prime.

It is a super-2 number, since 2×1550720567932 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (155072056723) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77536028396 + 77536028397.

It is an arithmetic number, because the mean of its divisors is an integer number (77536028397).

Almost surely, 2155072056793 is an apocalyptic number.

It is an amenable number.

155072056793 is a deficient number, since it is larger than the sum of its proper divisors (1).

155072056793 is an equidigital number, since it uses as much as digits as its factorization.

155072056793 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1984500, while the sum is 50.

The spelling of 155072056793 in words is "one hundred fifty-five billion, seventy-two million, fifty-six thousand, seven hundred ninety-three".