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155130064483 is a prime number
BaseRepresentation
bin1001000001111001111…
…0001110111001100011
3112211102021120210100211
42100132132032321203
510020201244030413
6155133223354551
714131160535322
oct2203636167143
9484367523324
10155130064483
115a876971569
12260948b2a57
1311823349c84
147718c2c0b9
15407e17883d
hex241e78ee63

155130064483 has 2 divisors, whose sum is σ = 155130064484. Its totient is φ = 155130064482.

The previous prime is 155130064457. The next prime is 155130064511. The reversal of 155130064483 is 384460031551.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 155130064483 - 25 = 155130064451 is a prime.

It is not a weakly prime, because it can be changed into another prime (155130064783) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77565032241 + 77565032242.

It is an arithmetic number, because the mean of its divisors is an integer number (77565032242).

Almost surely, 2155130064483 is an apocalyptic number.

155130064483 is a deficient number, since it is larger than the sum of its proper divisors (1).

155130064483 is an equidigital number, since it uses as much as digits as its factorization.

155130064483 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 172800, while the sum is 40.

The spelling of 155130064483 in words is "one hundred fifty-five billion, one hundred thirty million, sixty-four thousand, four hundred eighty-three".