Base | Representation |
---|---|
bin | 10110100100110011010… |
… | …001010000100001100001 |
3 | 12111022021210012212100101 |
4 | 112210303101100201201 |
5 | 200404122344343001 |
6 | 3144402144022401 |
7 | 220036506645055 |
oct | 26446321204141 |
9 | 5438253185311 |
10 | 1551343356001 |
11 | 548a1497670a |
12 | 2107b1901a01 |
13 | b33a259152a |
14 | 5512a565c65 |
15 | 2a549b45a01 |
hex | 16933450861 |
1551343356001 has 4 divisors (see below), whose sum is σ = 1557780465604. Its totient is φ = 1544906246400.
The previous prime is 1551343355911. The next prime is 1551343356011. The reversal of 1551343356001 is 1006533431551.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 500054051025 + 1051289304976 = 707145^2 + 1025324^2 .
It is a cyclic number.
It is not a de Polignac number, because 1551343356001 - 217 = 1551343224929 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1551343356011) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3218554440 + ... + 3218554921.
It is an arithmetic number, because the mean of its divisors is an integer number (389445116401).
Almost surely, 21551343356001 is an apocalyptic number.
It is an amenable number.
1551343356001 is a deficient number, since it is larger than the sum of its proper divisors (6437109603).
1551343356001 is an equidigital number, since it uses as much as digits as its factorization.
1551343356001 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6437109602.
The product of its (nonzero) digits is 81000, while the sum is 37.
Adding to 1551343356001 its reverse (1006533431551), we get a palindrome (2557876787552).
The spelling of 1551343356001 in words is "one trillion, five hundred fifty-one billion, three hundred forty-three million, three hundred fifty-six thousand, one".
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