Base | Representation |
---|---|
bin | 10110100110000111111… |
… | …110000111000110101001 |
3 | 12111102221211011101022010 |
4 | 112212013332013012221 |
5 | 200420030141300131 |
6 | 3145155145550133 |
7 | 220116643425441 |
oct | 26460776070651 |
9 | 5442854141263 |
10 | 1552764400041 |
11 | 549584029078 |
12 | 210b297a5349 |
13 | b356aaca6aa |
14 | 55223195121 |
15 | 2a5ce795b46 |
hex | 16987f871a9 |
1552764400041 has 4 divisors (see below), whose sum is σ = 2070352533392. Its totient is φ = 1035176266692.
The previous prime is 1552764400021. The next prime is 1552764400063. The reversal of 1552764400041 is 1400044672551.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is not a de Polignac number, because 1552764400041 - 211 = 1552764397993 is a prime.
It is a super-2 number, since 2×15527644000412 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (1552764400021) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 258794066671 + ... + 258794066676.
It is an arithmetic number, because the mean of its divisors is an integer number (517588133348).
Almost surely, 21552764400041 is an apocalyptic number.
It is an amenable number.
1552764400041 is a deficient number, since it is larger than the sum of its proper divisors (517588133351).
1552764400041 is an equidigital number, since it uses as much as digits as its factorization.
1552764400041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 517588133350.
The product of its (nonzero) digits is 134400, while the sum is 39.
The spelling of 1552764400041 in words is "one trillion, five hundred fifty-two billion, seven hundred sixty-four million, four hundred thousand, forty-one".
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