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155300113 = 1391117267
BaseRepresentation
bin10010100000110…
…11000100010001
3101211020001201001
421100123010101
5304224100423
623224342001
73564013003
oct1120330421
9354201631
10155300113
117a732301
1244014901
1326236477
14168a8373
15d979cad
hex941b111

155300113 has 4 divisors (see below), whose sum is σ = 156417520. Its totient is φ = 154182708.

The previous prime is 155300077. The next prime is 155300141. The reversal of 155300113 is 311003551.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311003551 = 619502429.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-155300113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (155300513) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 558495 + ... + 558772.

It is an arithmetic number, because the mean of its divisors is an integer number (39104380).

Almost surely, 2155300113 is an apocalyptic number.

It is an amenable number.

155300113 is a deficient number, since it is larger than the sum of its proper divisors (1117407).

155300113 is a wasteful number, since it uses less digits than its factorization.

155300113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1117406.

The product of its (nonzero) digits is 225, while the sum is 19.

The square root of 155300113 is about 12461.9465975425. The cubic root of 155300113 is about 537.5150028623.

Adding to 155300113 its reverse (311003551), we get a palindrome (466303664).

The spelling of 155300113 in words is "one hundred fifty-five million, three hundred thousand, one hundred thirteen".

Divisors: 1 139 1117267 155300113