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1553002344121 = 4853931994939
BaseRepresentation
bin10110100110010110001…
…001110010111010111001
312111110120101220012012211
4112212112021302322321
5200421022100002441
63145234525535121
7220125563056114
oct26462611627271
95443511805184
101553002344121
11549696377a78
12210b954144a1
13b35a81ab7c7
1455246a1357b
152a5e55e7a81
hex16996272eb9

1553002344121 has 4 divisors (see below), whose sum is σ = 1553034387600. Its totient is φ = 1552970300644.

The previous prime is 1553002344107. The next prime is 1553002344137. The reversal of 1553002344121 is 1214432003551.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1553002344121 - 215 = 1553002311353 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1553002344191) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15948931 + ... + 16046008.

It is an arithmetic number, because the mean of its divisors is an integer number (388258596900).

Almost surely, 21553002344121 is an apocalyptic number.

It is an amenable number.

1553002344121 is a deficient number, since it is larger than the sum of its proper divisors (32043479).

1553002344121 is an equidigital number, since it uses as much as digits as its factorization.

1553002344121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 32043478.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 1553002344121 its reverse (1214432003551), we get a palindrome (2767434347672).

The spelling of 1553002344121 in words is "one trillion, five hundred fifty-three billion, two million, three hundred forty-four thousand, one hundred twenty-one".

Divisors: 1 48539 31994939 1553002344121