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1553104131 = 31573297461
BaseRepresentation
bin101110010010010…
…0111110100000011
311000020102212100020
41130210213310003
511140043313011
6414040224523
753326111245
oct13444476403
94006385306
101553104131
11727761137
1237416b143
131b99c6537
1410a3a8095
1591539006
hex5c927d03

1553104131 has 8 divisors (see below), whose sum is σ = 2083995984. Its totient is φ = 1028807520.

The previous prime is 1553104121. The next prime is 1553104159. The reversal of 1553104131 is 1314013551.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1553104131 - 214 = 1553087747 is a prime.

It is a super-2 number, since 2×15531041312 = 4824264883458530322, which contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (1553104121) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1648260 + ... + 1649201.

It is an arithmetic number, because the mean of its divisors is an integer number (260499498).

Almost surely, 21553104131 is an apocalyptic number.

1553104131 is a deficient number, since it is larger than the sum of its proper divisors (530891853).

1553104131 is a wasteful number, since it uses less digits than its factorization.

1553104131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3297621.

The product of its (nonzero) digits is 900, while the sum is 24.

The square root of 1553104131 is about 39409.4421554023. The cubic root of 1553104131 is about 1158.0665699215.

Adding to 1553104131 its reverse (1314013551), we get a palindrome (2867117682).

The spelling of 1553104131 in words is "one billion, five hundred fifty-three million, one hundred four thousand, one hundred thirty-one".

Divisors: 1 3 157 471 3297461 9892383 517701377 1553104131