1553123145001 has 4 divisors (see below), whose sum is σ = 1589242287952. Its totient is φ = 1517004002052.

The previous prime is 1553123144971. The next prime is 1553123145019. The reversal of 1553123145001 is 1005413213551.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1553123145001 - 2⁷ = 1553123144873 is a prime.

It is a super-3 number, since 3×1553123145001³ (a number of 38 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1553123145061) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18059571411 + ... + 18059571496.

It is an arithmetic number, because the mean of its divisors is an integer number (397310571988).

Almost surely, 2^{1553123145001} is an apocalyptic number.

It is an amenable number.

1553123145001 is a deficient number, since it is larger than the sum of its proper divisors (36119142951).

1553123145001 is an equidigital number, since it uses as much as digits as its factorization.

1553123145001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36119142950.

The product of its (nonzero) digits is 9000, while the sum is 31.

Adding to 1553123145001 its reverse (1005413213551), we get a palindrome (2558536358552).

The spelling of 1553123145001 in words is "one trillion, five hundred fifty-three billion, one hundred twenty-three million, one hundred forty-five thousand, one".