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155335214131 is a prime number
BaseRepresentation
bin1001000010101010110…
…0110100010000110011
3112211221120121110202221
42100222230310100303
510021111303323011
6155205432421511
714136231351256
oct2205254642063
9484846543687
10155335214131
115a971751529
1226131547897
13118569b81b6
14773819109d
15409219d971
hex242ab34433

155335214131 has 2 divisors, whose sum is σ = 155335214132. Its totient is φ = 155335214130.

The previous prime is 155335214113. The next prime is 155335214171. The reversal of 155335214131 is 131412533551.

Together with previous prime (155335214113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 155335214131 - 237 = 17896260659 is a prime.

It is a super-2 number, since 2×1553352141312 (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (155335214171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77667607065 + 77667607066.

It is an arithmetic number, because the mean of its divisors is an integer number (77667607066).

Almost surely, 2155335214131 is an apocalyptic number.

155335214131 is a deficient number, since it is larger than the sum of its proper divisors (1).

155335214131 is an equidigital number, since it uses as much as digits as its factorization.

155335214131 is an evil number, because the sum of its binary digits is even.

The product of its digits is 27000, while the sum is 34.

Adding to 155335214131 its reverse (131412533551), we get a palindrome (286747747682).

The spelling of 155335214131 in words is "one hundred fifty-five billion, three hundred thirty-five million, two hundred fourteen thousand, one hundred thirty-one".