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1553924016761 is a prime number
BaseRepresentation
bin10110100111001101000…
…101101100101001111001
312111112221122012000101112
4112213031011230221321
5200424414022014021
63145510212330105
7220160454131264
oct26471505545171
95445848160345
101553924016761
1154a0196622a6
122111b2013935
13b36c4122a2c
14552d31b1cdb
152a64b4a5d5b
hex169cd16ca79

1553924016761 has 2 divisors, whose sum is σ = 1553924016762. Its totient is φ = 1553924016760.

The previous prime is 1553924016739. The next prime is 1553924016793. The reversal of 1553924016761 is 1676104293551.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1461091067536 + 92832949225 = 1208756^2 + 304685^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1553924016761 is a prime.

It is a super-2 number, since 2×15539240167612 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1553924012761) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 776962008380 + 776962008381.

It is an arithmetic number, because the mean of its divisors is an integer number (776962008381).

Almost surely, 21553924016761 is an apocalyptic number.

It is an amenable number.

1553924016761 is a deficient number, since it is larger than the sum of its proper divisors (1).

1553924016761 is an equidigital number, since it uses as much as digits as its factorization.

1553924016761 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1360800, while the sum is 50.

The spelling of 1553924016761 in words is "one trillion, five hundred fifty-three billion, nine hundred twenty-four million, sixteen thousand, seven hundred sixty-one".