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155445097125113 is a prime number
BaseRepresentation
bin100011010110000001100001…
…110010111101010011111001
3202101101101222002100121111122
4203112001201302331103321
5130333303024331000423
61310334254120435025
744512352262514445
oct4326014162752371
9671341862317448
10155445097125113
1145590993977754
1215526374618a75
136897543327713
142a55823477825
1512e873c7708c8
hex8d6061cbd4f9

155445097125113 has 2 divisors, whose sum is σ = 155445097125114. Its totient is φ = 155445097125112.

The previous prime is 155445097125053. The next prime is 155445097125179. The reversal of 155445097125113 is 311521790544551.

155445097125113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 96814422082624 + 58630675042489 = 9839432^2 + 7657067^2 .

It is a cyclic number.

It is not a de Polignac number, because 155445097125113 - 234 = 155427917255929 is a prime.

It is not a weakly prime, because it can be changed into another prime (155445097155113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77722548562556 + 77722548562557.

It is an arithmetic number, because the mean of its divisors is an integer number (77722548562557).

Almost surely, 2155445097125113 is an apocalyptic number.

It is an amenable number.

155445097125113 is a deficient number, since it is larger than the sum of its proper divisors (1).

155445097125113 is an equidigital number, since it uses as much as digits as its factorization.

155445097125113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3780000, while the sum is 53.

The spelling of 155445097125113 in words is "one hundred fifty-five trillion, four hundred forty-five billion, ninety-seven million, one hundred twenty-five thousand, one hundred thirteen".