Base | Representation |
---|---|
bin | 100011010110000001100001… |
… | …110010111101010011111001 |
3 | 202101101101222002100121111122 |
4 | 203112001201302331103321 |
5 | 130333303024331000423 |
6 | 1310334254120435025 |
7 | 44512352262514445 |
oct | 4326014162752371 |
9 | 671341862317448 |
10 | 155445097125113 |
11 | 45590993977754 |
12 | 15526374618a75 |
13 | 6897543327713 |
14 | 2a55823477825 |
15 | 12e873c7708c8 |
hex | 8d6061cbd4f9 |
155445097125113 has 2 divisors, whose sum is σ = 155445097125114. Its totient is φ = 155445097125112.
The previous prime is 155445097125053. The next prime is 155445097125179. The reversal of 155445097125113 is 311521790544551.
155445097125113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 96814422082624 + 58630675042489 = 9839432^2 + 7657067^2 .
It is a cyclic number.
It is not a de Polignac number, because 155445097125113 - 234 = 155427917255929 is a prime.
It is not a weakly prime, because it can be changed into another prime (155445097155113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77722548562556 + 77722548562557.
It is an arithmetic number, because the mean of its divisors is an integer number (77722548562557).
Almost surely, 2155445097125113 is an apocalyptic number.
It is an amenable number.
155445097125113 is a deficient number, since it is larger than the sum of its proper divisors (1).
155445097125113 is an equidigital number, since it uses as much as digits as its factorization.
155445097125113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3780000, while the sum is 53.
The spelling of 155445097125113 in words is "one hundred fifty-five trillion, four hundred forty-five billion, ninety-seven million, one hundred twenty-five thousand, one hundred thirteen".
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