Search a number
-
+
15555032018257 is a prime number
BaseRepresentation
bin1110001001011011000000…
…1010000110110101010001
32001002001020221000021110111
43202112300022012311101
54014323201144041012
653025514424001321
73163546123412044
oct342266012066521
961061227007414
1015555032018257
114a579410678a6
1218b2804900241
1388aaaa799664
143bac20862c5b
151be94e7baba7
hexe25b0286d51

15555032018257 has 2 divisors, whose sum is σ = 15555032018258. Its totient is φ = 15555032018256.

The previous prime is 15555032018221. The next prime is 15555032018329. The reversal of 15555032018257 is 75281023055551.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13063713869376 + 2491318148881 = 3614376^2 + 1578391^2 .

It is a cyclic number.

It is not a de Polignac number, because 15555032018257 - 215 = 15555031985489 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 15555032018257.

It is not a weakly prime, because it can be changed into another prime (15555032018657) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7777516009128 + 7777516009129.

It is an arithmetic number, because the mean of its divisors is an integer number (7777516009129).

Almost surely, 215555032018257 is an apocalyptic number.

It is an amenable number.

15555032018257 is a deficient number, since it is larger than the sum of its proper divisors (1).

15555032018257 is an equidigital number, since it uses as much as digits as its factorization.

15555032018257 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2100000, while the sum is 49.

The spelling of 15555032018257 in words is "fifteen trillion, five hundred fifty-five billion, thirty-two million, eighteen thousand, two hundred fifty-seven".